64k^2+4k=0

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Solution for 64k^2+4k=0 equation: 



64k^2+4k=0

a = 64; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·64·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*64}=\frac{-8}{128}
=-1/16
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*64}=\frac{0}{128}
=0
$

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